kookachu
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(sum of interior angles = 10 (n-2) where n is the number of sides of the polygon)

1. what is the sum of the interior angles of a pentagon?
2. if the sum of the interior angles of a polygon equals 1080, then determine the sides of the polygon.
3. what is a polygon called if the sim of its interior angles equals 6840?
4. what is the sum of the interior angles of an octagon?

Respuesta :

devishri1977

Answer:

Step-by-step explanation:

1) pentagon; n= 5

Sum of interior angles = 180*(n -2) = 180* (5-2) = 180 * 3 = 540

2) Sum of interior angles of a polygon = 1080

180*(n-2) = 1080

n - 2 = 1080/180

n -2 = 6

n = 6+2

n = 8

Polygon has 8 sides

3) Sum of interior angles of a polygon = 6840

180*(n-2) = 6840

n - 2 =6840/180

n -2 = 38

n = 38 + 2

n = 40

Polygon has 40sides

4)Sum of interior angles of an octagon = 180*(n-2) = 180* (8-2) = 180 - 6 = 1080

olivalopez

The sum of the interior angles of the 10-sided polygon on the left is 1440 °.

The answer is : 1440

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