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a pyramid has a horizontal square base of 12cm. the vertex of the pyramid is 7cm vertically above the base. calculate, correct to one decimal place:

(i) the length of the slant height

Respuesta :

Answer:

9.2 cm.

Step-by-step explanation:

A pyramid has a horizontal square base of 12 cm. The vertex of the pyramid is 7 cm vertically above the base.

So, the height of the pyramid is 7 cm and half-length i.e. half base is equal to [tex]\frac{12}{2} = 6[/tex] cm.

Now, the slant height of a pyramid is the altitude of the side triangles.

Therefore, the length of the slant height will be equal to [tex]\sqrt{6^{2} + 7^{2}} = 9.219[/tex] cm ≈ 9.2 cm. (Answer)