how many grams of ammonia (NH3) will react with
27.8 grams of nitric oxide (NO)?

4NH3 + 6NO → 5N2 + 6H2O

The molar mass of ammonia is 17.0337 grams and that of nitric oxide is 30.01 grams.

Respuesta :

The balanced chemical reaction is:

4NH3 + 6NO → 5N2 + 6H2O

We are given the amount of nitric oxide to be used in the reaction. This will be the starting point of the calculations.

27.8 g NO ( 1 mol NO / 30.01 g NO ) ( 4 mol NH3 / 6 mol NO ) ( 17.0337 g NH3 / 1 mol NH3 ) = 10.52 g NH3

The correct answer is

10.52

:)