The slope-intercept form of the equation of a line that passes through point (–2, –13) is y = 5x – 3. What is the point-slope form of the equation for this line?
y – 13 = 5(x – 2)
y + 13 = 5(x + 2)
y – 2 = 5(x – 13)
y + 2 = 5(x + 13)

Respuesta :

xSamx
The point-slope form in general is [tex]y-y_1=m(x-x_1)[/tex]

With the coordinate (-2,-13) being [tex](x_1,y_1)[/tex], and the slope m, is 5, from y = 5x – 3, 

[tex]y-y_1=m(x-x_1)[/tex]
[tex]y-(-13)=5(x-(-2))[/tex]
[tex]y+13=5(x+2)[/tex]

Answer:

its b :)

Step-by-step explanation:

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