Which set of ordered pairs could be generated by an exponential function?

A. (-1,-1/2), (0, 0),(1,1/2), (2, 1)

B. (–1, –1), (0, 0), (1, 1), (2, 8)

C. (-1,1/2), (0, 1), (1, 2), (2, 4)

D. (–1, 1), (0, 0), (1, 1), (2, 4)

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frika frika · Answer 1 · 2018-08-30T18:28:10+02:00

The graph of each exponential function [tex] y=a^x [/tex] passes through the point (0,1), because [tex] a^0=1.[/tex]

Thus, the only possible choice is C.

Check it:

[tex] \dfrac{1}{2}=a^{-1}, \Rightarrow a=2, [/tex]

[tex] 2=a^{1}, \Rightarrow a=2,[/tex]

[tex] 4=a^{2},\Rightarrow a=2. [/tex]

The set C could be generated by exponential function [tex] y=2^x. [/tex]

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MrRoyal MrRoyal · Answer 2 · 2022-05-11T10:47:46+02:00

The set of ordered pairs that could be generated by an exponential function is (c) (-1,1/2), (0, 1), (1, 2), (2, 4)

An exponential function is represented as:

y = ab^x

The above equation ensures that the value (0,0) cannot be found in an exponential function

The highlight above means that, the sets (a), (b) and (d) cannot generate an exponential equation because they contain the point (0,0)

Hence, the set of ordered pairs that could be generated by an exponential function is (c) (-1,1/2), (0, 1), (1, 2), (2, 4)

Read more about exponential functions at:

https://brainly.com/question/11464095

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