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What volume of Cl2 gas, measured at 682 torr and 37 ∘C, is required to form 29 g of NaCl?

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taskmasters
The balanced chemical reaction:

2Na + Cl2 = 2NaCl

We are given the amount of sodium chloride to be produced from the reaction. This will be the starting point of our calculations.

29 g NaCl ( 1 mol NaCl / 58.44 g NaCl ) ( 1 mol Cl2 / 2 mol NaCl ) = 0.25 mol Cl2

We use the ideal gas equation to solve for the volume of chlorine gas needed.

V = nRT / P
V = 0.25 (0.08206) (37+273.15) / (682/760)
V = 7.09 L Cl2