In average, each person in the industrialized world is responsible for the emission of 10,000 kg of carbon dioxide (CO2)(CO2) every year. This includes CO2CO2CO_2 that you generate directly, by burning fossil fuels to operate your car or your furnace, as well as CO2CO2CO_2 generated on your behalf by electric generating stations and manufacturing plants. CO2CO2CO_2 is a greenhouse gas that contributes to global warming. If you were to store your yearly emissions in a cube at STP, how long would each edge of the cube be?

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Answer:

The length of the cubical container will be 17.206 m.

Explanation:

Amount of carbon dioxide gas generated in year by person = 10,000 kg

1 kg = 1000 g

10,000 kg = 10,000 × 1000 g = 10,000,000 g

Moles of carbon dioxide = [tex]\frac{10,000,000 g}{44 g/mol}=227,272.72 mol[/tex]

Volume of carbon dioxide gas at STP= V

STP conditions = P = 1 atm , T = 273 K

Using Ideal gas equation ;

[tex]PV=nRT[/tex]

[tex]V=\frac{nRT}{P}=\frac{227,272.72mol\times 0.0821 atm L/mol K\times 273 K}{1 atm}[/tex]

[tex]V=5,093,931.82 L[/tex]

[tex]1 L = 0.001 m^3[/tex]

[tex]V=5,093,931.82 L=5,093,931.82 \times 0.001 m^3=5,093.93182 m^3[/tex]

Let the side of the cube = a

Volume of the cube = [tex]a^3[/tex]

[tex]V=5,093.93182 m^3[/tex]

[tex]a^3=5,093.93182 m^3[/tex]

[tex]a=\sqrt{5,093.93182 m^3}=17.206 m[/tex]

The length of the cubical container will be 17.206 m.

The study of chemicals and bonds is called chemistry.

The correct answer is 17.206 m.

Amount of carbon dioxide gas generated in year by person = 10,000 kg

1 kg = 1000 g

10,000 kg = 10,000 × 1000 g = 10,000,000g.

The moles of the carbon dioxide is as follows:-

[tex]\frac{mass}{molar mass} \\ \frac{10,000,000}{44}\\ =22,727,2[/tex]

What is ideal gas law?

  • The ideal gas law, also called the general gas equation, is the equation of the state of a hypothetical ideal gas.
  • It is a good approximation of the behavior of many gases under many conditions, although it has several limitations.

The formula is as follows:-

[tex]PV = nRT[/tex]

The volume of carbon dioxide gas at STP= V

  • STP conditions = P = 1 atm
  • T = 273 K

Using Ideal gas equation, placed all the values to the question.

[tex]v =\frac{nRT}{P} [/tex]

[tex]=\frac{227272*0.0821*273}{1} [/tex]

The volume will be :-5,093,931,82L

The side of the cube is as follows

[tex]a= \sqrt[1/3]{-5,093,931,82L} [/tex]

The value a= 17.20m

Hence, the length of the cube is 17.20m

For more information about the solid, refer to the link:-

https://brainly.com/question/6534096