Answer:
Explanation:
charge, q = 1.6 x 10^-19 C
distance, r = 911 nm = 911 x 10^-9 m
The Coulomb's force is given by
[tex]F=\frac{Kq_{1}q_{2}}{r^{2}}[/tex]
[tex]F=\frac{9\times 10^{9}\times 1.6\times 10^{-19}\times 1.6\times 10^{-19}}{\left (911\times 10^{-9} \right )^2}[/tex]
F = 2.78 x 10^-16 N
The force between the electron and the proton is 2.78 x 10^-16 N.