Answer:
a. 0.93 b. 0.06 c. 0.05
Step-by-step explanation:
Probability is commonly known as the chance of success of a particular event. The probability of failure of the event can also be estimated.
(a) Probability of not having type 2 defect is: [tex]P(A_{2}^{'})[/tex] [tex]= 1 - P(A_{2})[/tex] = 1 - 0.07 = 0.93
(b) Probability of having type 1 and 2 defects is: [tex]P(A_{1} n A_{2}) = P(A_{1}) + P(A_{2}) - P(A_{1}U A_{2}) = 0.12 + 0.07 - 0.13 = 0.06[/tex]
(c) probability pf having both type 1 and type 2 defects but not type 3 defect is:
[tex]P(A_{1} + A_{2} + A^{'} _{3}) = P(A_{1} n A_{2}) - P(A_{1} n A_{2} n A_{3}) = 0.06 - 0.01 = 0.05[/tex]
