contestada

Suppose you pluck a string on a guitar and it produces the note A at a frequency of 440 Hz . Now you press your finger down on the string against one of the frets, making this point the new end of the string. The newly shortened string has 4/5 the length of the full string. When you pluck the string, its frequency will be:
A. 350 Hz
B. 440 Hz
C. 490 Hz
D. 550 Hz

Respuesta :

Answer:

The newly frequency is 550 Hz.

(D) is correct option.

Explanation:

Given that,

Frequency = 440 Hz

Newly length [tex]L'=\dfrac{4}{5}L[/tex]

If the length of the string is L

We need to calculate the frequency

Using formula of frequency

[tex]f=\dfrac{v}{2L}[/tex]....(I)

We need to calculate the newly frequency

Using formula of frequency

[tex]f'=\dfrac{v}{2L'}[/tex]....(II)

Divided equation (II) and (I)

[tex]\dfrac{f'}{f}=\dfrac{L}{L'}[/tex]

Put the value into the formula

[tex]\dfrac{f'}{440}=\dfrac{L}{\dfrac{4}{5}L}[/tex]

[tex]f'=440\times\dfrac{5}{4}[/tex]

[tex]f'=550\ Hz[/tex]

Hence, The newly frequency is 550 Hz.

Otras preguntas