Answer:
62.4 square centimeters
Step-by-step explanation:
The picture of the question in the attached figure
we know that
The surface area of the triangular pyramid is equal to the area of the triangular base plus the area of its three lateral triangular faces
In this problem the triangles are equilateral, that means, the
surface area is equal to the area of four congruent equilateral triangles
so
[tex]A=4[\frac{1}{2}(b)(h)][/tex]
we have
[tex]b=6\ cm\\h=5.2\ cm[/tex]
substitute
[tex]A=4[\frac{1}{2}(6)(5.2)]=62.4\ cm^2[/tex]
