Respuesta :
Answer:
The price of machine A is less than that of machine B so the machine A will be bought
Explanation:
For the machine A
Total Duration required=6 years
Cost of Machine A=$24000
Operational Time=3 years
Salvage Value=$12000
So for the total time of 6 years
The machine A is to be bought for two times and salvaged for two times thus
Total Cost of Machine A for 6 years=(Cost of Machine-Salvage Value)*2
Total Cost of Machine A for 6 years=($24000-$12000)*2
Total Cost of Machine A for 6 years=($12000)*2
Total Cost of Machine A for 6 years=$24000
For the machine B
Total Duration required=6 years
Cost of Machine B=$30000
Operational Time=4 years
Salvage Value=$16000
So for the total time of 6 years
The machine B is to be bought for 1st time, the machine is to be salvaged and further the machine B is leased for the next two years at 9% interest compounded annually for $6000 per year
Total Cost of Machine B for 6 years=(Cost of Machine-Salvage Value)+(Leasing Cost)
Leasing Cost=First Installment+1st Interest+2nd Installment+2nd Interest
Leasing Cost=6000+2160+6000+1814=15974
Total Cost of Machine B for 6 years=(30000-16000)+(15974)
Total Cost of Machine B for 6 years=$29974
As the price of machine A is less than that of machine B so the machine A will be bought.
Answer: machine A should be purchased since the cost is lower than the cost of machine B
Explanation:
Cost - Salvage value / number of years
Cost = $24,000, salvage value = $12,000, n = 3 years
24,000 - 12,000 / 3
= 12,000 ÷ 3
= 4,000
The yearly depreciation =$,4000
Machine B
Cost = $30,000, Salvage value = $16,000, n = 4 years
30,000 - 16,000 / 4
= 14,000 ÷ 4
= 3,500
The yearly depreciation =$3,500
Since machine B can be lease for $6,000 per year
6,000 × 4 = 24,000
To determine which machine to be purchased
.Amount = P ( 1 + r /100)∧n
Machine A principal = $4,000, r = 9 ÷ 100 =0.09, n = 6
4,000 ( 1 + 0.09)∧6
4,000 (1.677100110841)
= 6,708.40 - 4,000
= 2,708.4
Machine B principal $3,500, r = 0.09, n = 6
3,500 (1 + 0.09)∧6
= 5,869.85 - 3,500
= 2,369.85
Amount + the amount earned from the lease of machine B
= 2,369.85 + 24,000
= 26,369.85
The machine A should be purchased, since machine B was initially purchased and the price is higher than machine A and since new machine can be purchased in the future at the same salvage value .