Respuesta :
Answer:
Step-by-step explanation:
Given that transitor has a 2% defective rate, need to calculate the probability that the 10th transistor produced is the first with a defect.
The probability function is p(x=k) = (1-p)^(n-1) * p
p = (1-defective rate)^(n-1) * defective rate; n=10
p = (1-0.02)^9 * 0.02 = 0.98^9 * 0.02 = 0.01666
Answer:
If you work this out with your TI84-Plus the steps are as follows:
you are looking for an exact case so you do: 2nd VARS geometpdf enter your values P: 0.02 and your x value:10 your answer is then 0.1829271931 round your to four decimals and it is 0.1829.
Step-by-step explanation:
