Respuesta :
Answer:
Step-by-step explanation:
Given that:
Let set A through f be defined as follows
A ={0 0 0}
B ={1 1 1}
C ={Ox: XE {(1,2)²}
D ={ 01x: XE(0,1)}
E = {1X:XE(0,1)²}
F= {00X:XE(0,1)}
a) (0,1)³=(0,1)×(0,1)×(0,1)
={(0,0), (0,1),(1,0),(1,1)} × (0,1)
={(0 0 0),(0 0 1),(0,1,0),(0,1,1),(1,0,0),(1,0,1),(1,1,0),(1,1,1)}
A={0,0,0}
B={(1,1,1)}
c={(0,0,0),(0,0,1),(0,1,0),(0,1,1)}
D={(0,1,0),(0,1,1)}
E={(1,0,0),(1,0,1)}
F={(0,0,0),(0,1,0)]
DUE UF is one partition
Since
1)DUEUF= (0,1)³
2)D∩E= E∩F=D∩F=∅
3)D≠∅, E≠∅ and F≠∅
2)CUE is another partition
Since
1) CUE=(0,1)³
2)C∩E =∅
3)C≠∅, E≠∅