Answer:
[tex]h=\frac{1}{6}[/tex]
Step-by-step explanation:
Given:
[tex]A=\frac{1}{2h} (B+b)\\[/tex]
[tex]A=21, B=2, b=5 ,h= ?[/tex]
We have to find the value of 'h'
So, putting the given values in the equation to find the value of 'h'.
[tex]A=\frac{1}{2h} (B+b)[/tex]
Implementing the given values in the given equations:
[tex]21=\frac{1}{2h}(2+5)\\\\ 21=\frac{1}{2h} (7)\\\\\frac{1}{2h}=\frac{21}{7}\\\\ \frac{1}{2h}=3 \\\\h=\frac{1}{6}[/tex]
So, the value of 'h' is
[tex]h=\frac{1}{6}[/tex]