Jim is trying to improve his speed on the track so he can qualify for the State Championships. As he is running, he goes from 70 meters/minute (beginning speed) to 106 meters/minute (final speed) in 9 seconds. What is his acceleration?

Respuesta :

Answer:

His acceleration is [tex]\frac{1}{15}[/tex] meters per seconds²

Step-by-step explanation:

Acceleration is the rate of change of the speed

The formula of acceleration is [tex]a=\frac{v_{f}-v_{i}}{t}[/tex] , where

  • [tex]v_{f}[/tex] is the final speed
  • [tex]v_{i}[/tex] is the initial speed
  • The unit of the acceleration is meters/second²

∵ Jim goes from 70 meters/minute (beginning speed) to

   106 meters/minute (final speed) in 9 seconds

∴ His initial speed [tex]v_{i}[/tex] = 70 meters/minute

- Change it the meter per second

∵ 1 minute = 60 seconds

∴ [tex]\frac{70}{(1)(60)}=\frac{70}{60}=\frac{7}{6}[/tex]  meters/second

∴ [tex]v_{i}[/tex] = [tex]\frac{7}{6}[/tex]  meters/second

∵ His final speed [tex]v_{f}[/tex] = 106 meters/minute

- Change it the meter per second

∴ [tex]\frac{106}{(1)(60)}=\frac{106}{60}=\frac{53}{30}[/tex]  meters/second

∴ [tex]v_{f}[/tex] = [tex]\frac{53}{30}[/tex]  meters/second

∵ The time of the change of his speed is 9 seconds

∴ t = 9

∵ The formula of acceleration is [tex]a=\frac{v_{f}-v_{i}}{t}[/tex]

- Substitute the values of t, [tex]v_{i}[/tex]  and [tex]v_{f}[/tex] in the formula above

∴  [tex]a=\frac{\frac{53}{30}-\frac{7}{6}}{9}=\frac{1}{15}[/tex]

His acceleration is [tex]\frac{1}{15}[/tex] meters per seconds²