Answer:
[tex]\large \boxed{\text{0.64 mol/L}}[/tex]
Explanation:
The original solution was diluted from 250 mL to 295 mL
We can use the dilution formula to calculate the concentration of the diluted solution.
[tex]\begin{array}{rcl}V_{1}c_{1} & = & V_{2}c_{2}\\\text{250 mL }\times \text{0.75 mol/L} & = & \text{295 mL} \times c_{2}\\c_{2}& = & \dfrac{250}{295}\times \text{0.75 mol/L}\\\\& = & \text{0.64 mol/L}\\\end{array}\\\text{The molar concentration of the diluted solution is $\large \boxed{\textbf{0.64 mol/L}}$}[/tex]
The amount of material in a particular volume of the solution is measured in molarity that describes as the mole number of solute in 1 liter of solution that is referred to as molarity.
Its original solutions were reduced in volume from 250 mL to 295 mL. You could use the dilution method to calculate the quantity of the solution.
Given:
[tex]V_1= 250 \ ml\\\\ c_1= 0.75 \frac{mol}{L} \\\\ V_2=295\ ml \\\\[/tex]
To find:
[tex]c_2=?\\\\[/tex]
Solution:
Using formula:
[tex]\bold{V_1c_1=V_2c_2}\\\\[/tex]
Apply value into the formula:
[tex]\to \bold{(250 \ ml) \times (0.75 \frac{mol}{L}) = 295\ mL \times c_2}\\\\\bold{c_2=\frac{250}{295}\times 0.75 \frac{mol}{L}}\\\\[/tex]
[tex]\bold{=0.847\times 0.75 \frac{mol}{L}}\\\\\bold{=0.64 \ \frac{mol}{L}}[/tex]
Therefore, the final answer is "0.64 mol/L".
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