Answer:
A is the correct answer.
Step-by-step explanation:
[tex] \tan x = \frac{6}{8} = \frac{opposite \: side \: to \: \angle \: x}{adjacent \: side \: to \: \angle \: x} \\ \\ hypotenuse \\ = \sqrt{ {(opp. \: side)}^{2} + {(adj. \: side)}^{2} } \\ = \sqrt{ {6}^{2} + {8}^{2} } \\ = \sqrt{36 + 64} \\ = \sqrt{100} \\ = 10 \\ \\ \because \sin (x) = \frac{opposite \: side \: to \: \angle \: x}{hypotenuse} \\ \\ \huge{ \red{ \boxed{\therefore \: \sin (x) = \frac{6}{10}}}} \\ \\ \cos (x) = \frac{adjacent \: side \: to \: \angle \: x}{hypotenuse} \\ \\ \huge{ \purple{ \boxed{\therefore \: \cos (x) = \frac{8}{10} }}} \\ [/tex]
Thus, option A is the correct answer.
