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A survey for brand recognition is done and it is determined that 68% of consumers have heard of Dull Computer Company. A survey of 800 randomly selected consumers is to be conducted. For such groups of 800, would it be unusual get 556 consumers who recognize the Dull Computer Company name?

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Answer:

No, it would be usual

Step-by-step explanation:

The mean will be [tex]\frac {68}{100}\times 800=544[/tex]

Standard deviation[tex]s=\sqrt {np(1-p)}=\sqrt {800*0.68*(1-0.68)}=13.2[/tex]

The confidence level will be mean±2*standard deviation

Confidence level= 544±2*13.2=544±26.6 hence 517.6 or 570.4

Getting 556 consumers who recognize the Dull Computer Company name won't be unusual because it's within limits

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