The figure shows the front side of a metal desk in the shape of a trapezoid. What is the area of this trapezoid? 10 ft² 16 ft² 32 ft² 61 ft² Isosceles trapezoid A B C D with parallel sides BC and A D. A D is 5 feet. B C is 3 feet. A dotted segment runs from B to E where E is on side A D and angle B E F is a right angle. A dotted segment runs from point C to F where F is on side A D. Angle C F E is a right angle. C F is 4 feet. if u answer corretcly ill give u brainliest
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Answer:

The area of the trapezoid is 16 feet² 2nd answered

Step-by-step explanation:

ABCD is a trapezoid where

  • AD is parallel to BC
  • BE and CF are perpendicular to AD
  • AD = 5 feet
  • BC = 3 feet

∵ ABCD is a trapezoid

∵ AD // BC

∴ AD and BC are the bases of the trapezoid

∵ ∠BEF is a right angle

∵ ∠CFE is a right angle

∵ E and F are on the side AD

∴ BE and CF are perpendicular  to AD

∴ BE and CF are the heights of the trapezoid ABCD

The formula of the area of a trapezoid is [tex]A=\frac{1}{2}(b_{1}+b_{2})h[/tex] , where

[tex]b_{1}[/tex] and [tex]b_{2}[/tex] are its parallel sides and h is its height

∵ AD and BC are the bases of the trapezoid

∵ AD = 5 feet and BC = 3 feet

∴ [tex]b_{1}[/tex] = 5 and [tex]b_{2}[/tex] = 3

∵ CF is the height of the trapezoid

∵ CF = 4 feet

∴ h = 4

- Substitute all of these values in the formula of the area

∴ [tex]A=\frac{1}{2}(5+3)(4)[/tex]

∴ A = 16 feet²

The area of the trapezoid is 16 feet²

Answer:

11

Step-by-step explanation: