Respuesta :

Answer:

4 mph

Step-by-step explanation:

The average speed of an object is given by the total distance covered by the time taken:

[tex]v=\frac{d}{t}[/tex]

where

d is the total distance covered

t is the time taken

in the first part, the person runs for 0.4 hours at a speed of 7 mph, so the distance covered in the 1st part is

[tex]d_1 = v_1 t_1 = (7)(0.4)=2.8 mi[/tex]

Then the distance covered in the second part is [tex]d_2[/tex], so the total distance is

[tex]d=2.8+d_2[/tex] (1)

The total time elapsed is 0.4 hours (first part) + 0.8 hours (second part), so

[tex]t=0.4+0.8=1.2 h[/tex]

So we can write the average speed as

[tex]v=\frac{2.8+d_2}{1.2}[/tex] (1)

We want the average speed to be 5 mph,

v = 5 mph

Therefore we can rearrange eq.(1) to find d2:

[tex]d_2 = 1.2v-2.8 = (1.2)(5)-2.8=3.2 mi[/tex]

And therefore, the speed in the second part must be

[tex]v_2=\frac{d_2}{t_2}=\frac{3.2}{0.8}=4 mph[/tex]

Answer:

4 mph

Step-by-step explanation:

The average speed of an object is given by the total distance covered by the time taken:

where

d is the total distance covered

t is the time taken

in the first part, the person runs for 0.4 hours at a speed of 7 mph, so the distance covered in the 1st part is

Then the distance covered in the second part is , so the total distance is

(1)

The total time elapsed is 0.4 hours (first part) + 0.8 hours (second part), so

So we can write the average speed as

(1)

We want the average speed to be 5 mph,

v = 5 mph

Therefore we can rearrange eq.(1) to find d2:

And therefore, the speed in the second part must be