Answer:
a. [tex](6s-5s)+3=\frac{1}{12}-\frac{1}{6}[/tex]
b. [tex]s=-\frac{37}{12}[/tex]
Step-by-step explanation:
You need to remember that:
1. The word "more" indicates Addition.
2. The "Difference" is the result of a Subtraction.
a. Then, knowing this information, you know that:
- "The difference of [tex]6s[/tex] and [tex]5s[/tex]" must be expressed as:
[tex]6s-5s[/tex]
- Then, "Three more than the difference of [tex]6s[/tex] and [tex]5s[/tex] " is:
[tex](6s-5s)+3[/tex]
- "The difference of [tex]\frac{1}{12}[/tex] and [tex]\frac{1}{6}[/tex] " can be expressed in this form:
[tex]\frac{1}{12}-\frac{1}{6}[/tex]
Therefore, "Three more than the difference of [tex]6s[/tex] and [tex]5s[/tex] is equal to the difference of [tex]\frac{1}{12}[/tex] and [tex]\frac{1}{6}[/tex] " is:
[tex](6s-5s)+3=\frac{1}{12}-\frac{1}{6}[/tex]
b. Solve for "s" in order to find its value:
[tex]s+3=-\frac{1}{12}\\\\12(s+3)=-1\\\\12s+36=-1\\\\12s=-1-36\\\\s=-\frac{37}{12}[/tex]
the solution will be,
[tex]s=\dfrac{-37}{12}[/tex].
Given,
three more than the difference of [tex]6 \rms s[/tex] and [tex]5\rms s[/tex] is equal to the difference of [tex]\frac{1}{12}[/tex] and [tex]\frac{1}{6}[/tex].
So,
[tex](6s -5s)+3=\frac{1}{12} -\frac{1}{6}[/tex]
[tex]s+3=\frac{1-2}{12} \\\\s+3=\frac{-1}{12}[/tex]
[tex]s=\frac{-1}{12} -3[/tex]
Or, [tex]s=\frac{-37}{12}[/tex]
Hence the solution will be,
[tex]s=\dfrac{-37}{12}[/tex].
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https://brainly.com/question/4042361
