Sara has a son and a daughter – Billy and Jane. Billy is five times as old as Jane. Their mother is now three times as old as Billy, and in 2 years she will be eight times as old as Jane. Find the present age of the mother.

Respuesta :

Answer:

The present age of the mother is 30 years

Step-by-step explanation:

Let

x ---> Sara's age (the mother)

y ---> Billy's age (the son)

z ---> Jane's age (the daughter)

we know that

Billy is five times as old as Jane

so

[tex]y=5z[/tex] ----> equation A

Their mother is now three times as old as Billy

[tex]x=3y[/tex] ----> equation B

Their mother in 2 years she will be eight times as old as Jane

so

[tex]x+2=8(z+2)[/tex] ---> equation C

substitute equation A in equation B

[tex]x=3(5z)[/tex]

[tex]x=15z[/tex] ----> equation D

substitute equation D in equation C

[tex]15z+2=8(z+2)[/tex]

solve for z

[tex]15z+2=8z+16\\15z-8z=16-2\\7z=14\\z=2[/tex]

Find the value of x

[tex]x=15(2)=30[/tex]

therefore

The present age of the mother is 30 years