Answer:
[tex]\large \boxed{\$9.00}[/tex]
Step-by-step explanation:
Let p = the original price of the ticket
[tex]\begin{array}{rcl}\text{ Price before discount - discount} & = & \text{sale price}\\p - 0.15p & = & 7.65\\0.85p & = & 7.65\\p & = & \dfrac{7.65 }{0.85}\\\\& = & \mathbf{9.00}\\\end{array}\\\text{The original price of the ticket was $\large \boxed{\mathbf{\$9.00}}$}[/tex]
Check:
[tex]\begin{array}{rcl}9.00 - 0.15(9.00) & = & 7.65\\9.00 - 1.35 & = & 7.65\\7.65 & = & 7.65\\\end{array}[/tex]
OK.
