Respuesta :

dillonliyanage

Answer:

65°*2 = 130° - since it's an isosceles triangle.

180- 130 = 50° (∠A, usually in the middle of 2 other letters ∠BAC)                  ( total angles in a triangle = 180° )

∠X = ∠BAC = 50° - since they are alternate angles

This is because of the parallel lines.

In this case we got a Z shape, so ∠x would be = ∠BAC

Hrishii

Step-by-step explanation:

In [tex] \triangle ABC, \: AB \cong AC\\

\therefore m\angle ACB = m\angle ABC= 65\degree\\(\angle s\:opposite \:to\:equal\: sides) \\\\

AB \parallel DC.. (given) \\\

\therefore m\angle ABC= m\angle DCE= 65\degree\\(corresponding \:\angle s) \\\\

\therefore m\angle ACB+x+m\angle DCE = 180\degree \\\\

\therefore 65\degree+x+65\degree = 180\degree \\\\

\therefore x+130\degree = 180\degree \\\\

\therefore x= 180\degree -130\degree \\\\

\huge \red {\boxed {\therefore x= 50\degree}} \\\\[/tex]

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