Answer:
channel capacity for a teleprinter channel is 474.76 bit per sec
Explanation:
given data
bandwidth = 300 HZ
signal-to-noise ratio = 3 dB
solution
we use here decibel formula that is
SNR(dB) = 10 × log (SNR) ..............1
here SNR is signal-to-noise ratio
so put here value we get
3 = 10 × log( SNR)
SNR = [tex]10^{0.3}[/tex] = 1.995
and now we use here Shannon equation that is
C = B × [tex]log_2[/tex] ( 1+SNR) ...............2
here C is channel capacity
put here value and we get
C = 300 × [tex]log_2[/tex] ( 1+ 1.995 )
C = 474.76
so channel capacity for a teleprinter channel is 474.76 bit per sec
