Respuesta :

Answer:

The space that NH3 occupies is 1,205L

Explanation:

Using the ideal gas law we can find the volume of the gas

[tex]PV=nRT\\[/tex]

Where:

  • P is the pressure of the gas in Torr
  • V is the volume of the gas in Liters
  • n are the moles of gas
  • T is the temperature of the gas in Kelvin
  • R is the gas constant (62,36 L.Torr/K.mol)

First, we convert the temperature to kelvin, and find the moles of gas using the mass and molecular weight of NH3

T(K)= °C + 273,15= 40 + 273= 313K

[tex]n=\frac{Mass(g)}{Molecular Weight(g/mol)} \\\\n= \frac{955g}{17g/mol} = 56,18mol[/tex]

Now we find the volume with the ideal gas law

[tex]V=\frac{nRT}{P} \\\\V=\frac{(56,18mol)(62,36L.atm/K.mol)(313,15K)}{910Torr} \\\\V=1,205L[/tex]

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