Answer:
Angle θ ≅ 21.5°
Explanation:
Given:
speed Vi= 60 m/s, Range R= 250 m, g=9.81 m/s²
To find:
Angle θ = ?
Sol: we know that Rang R = Vi² sin 2θ / g
⇒ Sin 2θ = g×R / Vi²
Sin 2θ = (9.81 m/s² × 250 m) / ( 60 m/s)²
Sin 2θ = 0.68125
2θ = Sin ⁻¹ (0.68125)
2θ = 42.9413
θ = 42.9413 / 2
θ = 21.4706 ≅ 21.5°
