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A copper-constantan thermocouple is to be used to measure temperatures between 0 and 200°C. The e.m.f. at 0°C is 0 mV, at 100°C it is 4.277 mV and at 200°C it is 9.286 mV. What will be the non-linearity error at 100°C as a percentage of the full range output if a linear relationship is assumed between e.m.f. and temperature over the full range?

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Answer:

3.941%

Explanation:

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The non-linearity error at 100°C as a percentage of the full range output  is; 3.941%

Thermocouple calculations

The slope of the copper - constantan thermocouple is;

m = (V₂ - V₁)/(T₂ - T₁)

We are given;

V₁ = 0 mV

T₁ = 0

T₂ = 200°C

V₂ = 9.286 mV

Slope = (9.286 - 0)/(200 - 0)

Slope = 0.04643 mV/°C

At 100°C, slope = 0.04643 mV/°C/100 = 4.643 mV

Formula for Non-linearity error is;

Error = Measured Value - Theoretical Value

Error = 4.277 - 4.643

Error = -0.366

error as percentage of full range output = 0.366/9.286 * 100%

error as percentage of full range output = 3.941%

Read more about Thermocouples at; https://brainly.com/question/16412550

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