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You are on an airplane that is landing. The plane in front of your plane blows a tire. The pilot of your plane is advised to abort the landing, so he pulls up, moving in a semicircular upward-bending path. The path has a radius of 490 mm with a radial acceleration of 18 m/s2m/s2.?

Respuesta :

Answer:

Speed of the plane will be equal to 2.969 m/sec

Explanation:

Note - It is not given but we have to find the speed of the plane.

We have given radius r = [tex]r=490mm=490\times 10^{-3}m[/tex]

Angular acceleration [tex]a=18m/sec^2[/tex]

We have to fond the speed of the plane

We know that angular acceleration is equal to [tex]a=\frac{v^2}{r}[/tex]

So [tex]18=\frac{v^2}{490\times 10^{-3}}[/tex]

[tex]v^2=8.82[/tex]

v = 2.969 m/sec

So speed of the plane will be equal to 2.969 m/sec

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