Answer:
The number of germanium atoms per cubic centimeter for this germanium-silicon alloy is 3.16 x 10²¹ atoms/cm³.
Explanation:
Concentration of Ge ([tex]C_{Ge}[/tex]) = 15%
Concentration of Si (C[tex]_{Si}[/tex]) = 85%
Density of Germanium (ρ[tex]_{Ge}[/tex]) = 5.32 g/cm³
Density of Silicon (ρ[tex]_{Si}[/tex]) = 2.33 g/cm³
Atomic mass of Ge (A[tex]_{Ge}[/tex])= 72.64 g/mol
To calculate the number of Ge atoms per cubic centimeter for the alloy, we will use the formula:
No of Ge atoms/cm³=[Avogadro's Number*[tex]C_{Ge}[/tex]]/([[tex]C_{Ge}[/tex]*A[tex]_{Ge}[/tex]/ρ[tex]_{Ge}[/tex])+(C[tex]_{Si}[/tex]*A[tex]_{Ge}[/tex]/ρ[tex]_{Si}[/tex])]
= (6.02x10²³ * 15%) / [(15% * 72.64/5.32)+(72.64*85%/2.33)]
= (9.03x10²²)/(2.048+26.499)
= (9.03x10²²)/(28.547)
No of Ge atoms/cm³ = 3.16 x 10²¹ atoms/cm³
