Answer:
[tex]15.625m/s^2[/tex]
Explanation:
We us the third equation of a uniformly accelerated motion.
[tex]v^2=u^2+2as.................(1)[/tex]
where v is the final velocity, u the initial velocity, a the acceleration and s the distance covered.
Given;
v = 15m/s
u = 10m/s
the distance covered is given by;
[tex]s=x_2-x_1...............(2)[/tex]
where,
[tex]x_2=10.0m\\x_1=6.0m[/tex]
Therefore,
[tex]s=10.0-6.0\\s=4.0m[/tex]
Substituting all values into equation (1);
[tex]15^2=10^2+2*a*4\\225=100+8a\\8a=225-100\\8a=125\\a=\frac{125}{8}\\a=15.625m/s^2[/tex]
