Respuesta :
The expression gives the number of transistors in a dense integrated circuit in 1979 is:
[tex]y = 5000(1+0.41)^5\\\\or\\\\y = 5000(1.41)^5[/tex]
Solution:
The increasing function is given as:
[tex]y = a(1+r)^t[/tex]
Where,
y is the future value
a is the initial value
r is the growth rate
t is the number of years
From given,
a = 5000
[tex]r = 41 \% = \frac{41}{100} = 0.41[/tex]
t = 1974 to 1979 = 5 years
Substituting the values in formula,
[tex]y = 5000(1+0.41)^5\\\\y = 5000(1.41)^5[/tex]
Thus the expression gives the number of transistors in a dense integrated circuit in 1979 is found
