The trajectory of an object having horizontal motion in free fall is the path of a projectile
a. The height of the cliff is approximately 30.66 meters
b. The distance from the base of the cliff where the driver hits the water is 9.5 meters
The reason the above values are correct are given as follows:
Known parameters:
Horizontal speed of the car, vₓ = 3.8 m/s
Time it takes the car to reach the water, t = 2.5 s
Required parameter:
a. The height of the cliff
Solution:
The equation of free fall for the car is [tex]h = u\cdot t + \dfrac{1}{2} \cdot g \cdot t^2[/tex]
Where;
u = Initial vertical velocity = 0 for horizontally driving car
h = The vertical distance travelled = The height of the cliff
t = The time of motion = 2.5 s
g = Acceleration due to gravity ≈ 9.8 m/s²
Plugging in the values gives;
[tex]h = 0\times 2.5 + \dfrac{1}{2} \times 9.81 \times 2.5^2 \approx 30.66[/tex]
The height of the cliff, h ≈ 30.66 meters
b. The distance from the base of the cliff the driver hit the water is given as follows;
The distance from the base of the cliff where the driver hits the water is the horizontal distance, given by the product of the horizontal speed and the time of motion as follows;
Horizontal distance, d = vₓ × t
∴ d = 3.8 m/s × 2.5 s = 9.5 m
The distance from the base of the cliff where the driver hits the water, d = 9.5 m
Learn more about the projectile motion here:
https://brainly.com/question/21420744
