Answer:
0.0792
Step-by-step explanation:
the probability that a family owns a dog= P(D)=36%=0.36
the probability that a family owns a dog also owns a cat=P(CnD)=22%=0.22
the probability that a family owns a cat =P(C)=30%=0.3
therefore, Probability that a randomly selected family owns both a dog and cat is given as
P(C∪D) = P(C∩D)×P(D)
=0.22×0.36
=0.0792
≈0.08