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GeF 3H is formed from GeH 4 and GeF 4 in the combination reaction: GeH 4 3GeF 4 4GeF 3H If the reaction yield is 92.6%, how many moles of GeF 4 are needed to produce 8.00 mol of GeF 3H

Respuesta :

osagieosazeme72

Answer:

6.48

Explanation:

GeH4 + 3 GeF4 > 4 GeF3H

3 moles of GeF4 react to form 4 moles of GeF4

Therefore, (8 x 3/4)/0.926

= 6.48 moles