Answer: The number of moles of oxygen gas in the container is 0.0049 moles
Explanation:
To calculate the moles of oxygen gas, we use the equation given by ideal gas which follows:
[tex]PV=nRT[/tex]
where,
P = pressure of the gas = 0.12 atm
V = Volume of the gas = 1.0 L
T = Temperature of the gas = [tex]25^oC=[25+273]K=298K[/tex]
R = Gas constant = [tex]0.0821\text{ L. atm }mol^{-1}K^{-1}[/tex]
n = number of moles of oxygen gas = ?
Putting values in above equation, we get:
[tex]0.12atm\times 1.0L=n\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 298K\\\\n=\frac{0.12\times 1.0}{0.0821\times 298}=0.0049mol[/tex]
Hence, the number of moles of oxygen gas in the container is 0.0049 moles
