0.162 moles of CO₂ are produced by this reaction.
Chemical reaction:
C₃H₈(g) + 5O₂(g) → 3CO₂(g) +4H₂O(g)
As we have the volume of propane, we need to know the mass that has reacted, so we apply density's concept.
Calculation for Density:
[tex]\text{ Density} = \frac{\text{ Mass}}{\text{Volume}}\\\\\text{ Mass}= \text{ Density} * \text{Volume}\\\\\text{ Mass}= 0.00183 g/mL * 1300 mL \\\\\text{ Mass}= 2.379 g[/tex]
Determination for moles:
[tex]\text{Number of moles} =\frac{\text{Given mass}}{\text{Molar mass}}\\\\ \text{Number of moles} =\frac{2.379 g}{44 g }\\\\ \text{Number of moles}=0.054 moles[/tex]
Ratio is 1: 3, 1 mol of propane can produce 3 moles of carbon dioxide.
Then, 0.054 moles may produce (0.054 .3)/1 = 0.162 moles.
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