Respuesta :
0.442
Step-by-step explanation:
Step 1 :
Given that 11% of the lights are defective.
So probability of a light randomly chosen is defective is .11
This implies probability of a light randomly chosen is not defective is 1 - .11 = .89
Step 2 :
In a pack of 5 light bulbs the probability that none of them are defective is (0.89)^ 5
Hence the probability that at least one of the light bulbs is defective is
1-(0.89)^ 5 = 1 - 0.558 = 0.442
The probability that at least one of the light bulbs is defective is 0.442.
Calculation of the probability:
Since 11% of the lights are defective.
Now the probability of not defective should be
= 1 - .11
= .89
Now the probability that at least one of the light bulbs should be defective is
[tex]= 1-(0.89)^ 5[/tex]
= 1 - 0.558
= 0.442
hence, The probability that at least one of the light bulbs is defective is 0.442.
Learn more about probability here: https://brainly.com/question/24760080
