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You measure the power delivered by a battery to be 5.83 W when it is connected in series with two equal resistors. How much power will the same battery deliver if the resistors are now connected in parallel across it

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Olajidey

Answer:

P = 23.32 W

Explanation:

In series  

equivalent Resistance

R(eq)=R+R=2R

In parallel equivalent resistance

R(eq) = R*R/(R+R) =R/2

since.

power

P=V² / R

in series

⇒V = √(P*R)

=√(5.83*2R )

=√(11.66R)

in parallel

P = V² / R(eq)

=(√(11.66R)²) / (R/2)

P=11.66 * R * 2/R

P = 23.32 W

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