contestada

Consider the line 4x - 2y=-5.
Find the equation of the line that is perpendicular to this line and passes through the point (-1, -2).

Respuesta :

davidalokam

Answer:

2y+x = -5

Step-by-step explanation:

From 4x - 2y = -5

-2y = -4x-5

Divide through by -2

y = 2x + 5/2 comparing with y = mx +c

m1= 2

For perpendicularity: m1m2 = -1

m2 = -1/2

equation passing through (-1,-2) and perpendicular to 4x-2y =-5 is:

y-y1 = m2(x-x1)

y-(-2) = -1/2(x-(-1)) = -1/2(x+1)

y+2 = -x/2 - 1/2

Multiply through by 2

2y + 4 = -x - 1

2y=-x-1-4

2y=-x-5

2y+x = -5