Answer:
torque τ = 24 N-m
torque τ = 11.98 N-m
Explanation:
given data
mass of the ball = 1.5 kg
arm length l = 70 cm = 0.7 m
mass of arm = 4 kg
solution
we get here center of mass that is
center of mass = [tex]\frac{m1*x1+m2x2}{m1+m2}[/tex] ..........1
center of mass = [tex]\frac{4*.35+1.5*0.7}{4+1.5}[/tex]
center of mass = 0.44545 m
and
torque will be
torque τ = F × r ×sinθ ...........2
torque τ = (4+1.5)9.8 × 0.4454 × sin90
torque τ = 24 N-m
and now we get magnitude of the torque
magnitude of the torque τ = F × r ×sinθ
magnitude of the torque τ = (4+1.5)9.8 × 0.4454 × sin60
magnitude of the torque τ = 11.98 N-m
