Answer:
1,499 liter
Step-by-step explanation:
The rest of the question is:
each is in the shape of a cylinder of radius 21 cm and height is 50 cm.
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The quantity of water left in the tanker after distribution
= Total quantity - Distributed quantity
Total quantity = Volume of the giving figure
= Volume of the cylinder + volume of 2 hemispheres
Volume of the cylinder of 4.2 m length and 1.2 m of a diameter.
L = 4.2 and radius = r = 0.5 * diameter = 0.5 * 1.2 = 0.6
Volume of cylinder = π r² L = (22/7) * 0.6² * 4.2 = 4.752 m³
Volume of 2 hemispheres = 2*0.5 * (4/3) π r³ = (4/3) * (22/7) * 0.6³
=792/875 m³
Total volume = 4.752 + 792/875 = 198/35 ≈ 5.657 m³
Distributed quantity = 60 times the volume of a cylinder of radius 21 cm and height is 50 cm
Distributed quantity = 60 * π r² L = 60 * (22/7) * 21² * 50 = 4,158,000 cm³
Since 1 m³= 1,000,000 cm³
Distributed quantity = 4,158,000 cm³ = 4.158 m³
The quantity of water left in the tanker after distribution =
= 198/35 - 4.158 ≈ 1.499 m³
Since 1 m³= 1,000 liter
The quantity of water left in the tanker after distribution =
= 1.499 m³ = 1.499 * 1000 = 1,499 liter
Answer:
142 liters
Step-by-step explanation:
The following information is missing:
"if they distributing drinking water to 60 people in a container each in shape of cylinder of radius 21 cm and height 50 cm"
If we subtract the two hemispheres, the length of the tank is 4.2 -1.2 = 3 m. The tank is composed by an sphere and a cylinder (with a diameter = 1.2 m). Then, its volume is
Volume of the tank = π*D²/4*lenght + 4/3*π*D³/8
Volume of the tank = 22/7*1.2²/4*3 + 4/3*22/7*1.2³/8 = 4.3 m³
On the other hand, each small container is a cylinder of radius 0.21 m and height 0.5 m. Each one has a volume of:
Volume of the small container = π*r²*height
Volume of the small container = 22/7*0.21²*0.5 = 0.0693 m³
For 60 containers the total volume is 0.0693*60 = 4.158 m³
Then, the volume left in the tank after the distribution is 4.3 - 4.158 = 0.142 m³ or 142 liters
