Respuesta :
Answer:
t = 22.32 s
Explanation:
The kinetics of a reaction can be known graphically by plotting the concentration vs time experimental data on a sheet of graph.
- The concentration vs time graph of zero order reactions is linear with negative slope.
- The concentration vs time graph for a first order reactions is a exponential curve. For first order kinetics the graph between the natural logarithm of the concentration vs time comes out to be a straight graph with negative slope.
- The concentration vs time graph for a second order reaction is a hyperbolic curve. Also, for second order kinetics the graph between the reciprocal of the concentration vs time comes out to be a straight graph with positive slope.
Given that:- 1/[A] vs. time is linear which means it follows second order kinetics.
Thus,
Given that slope = k = 0.056 M⁻¹ s⁻¹.
Integrated rate law for second order kinetic is:
[tex]\frac{1}{[A_t]} = \frac{1}{[A]_0}+kt[/tex]
Where, [tex][A_t][/tex] is the final concentration = Half of the initial concentration = 0.80 /2 M = 0.40 M
[tex][A_0][/tex] is the initial concentration = 0.80 M
So,
[tex]\frac{1}{0.40} = \frac{1}{0.80}+0.056\times t[/tex]
t = 22.32 s
