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A social sciences researcher wants to know about the amount of money that couples without children spend on leisure travel. Her sample of 280 couples yields a mean of $1263.00 and a standard deviation of $160.00. What is the margin of error for a 95% confidence interval?

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jepessoa

Answer:

$18.74

Explanation:

the margin of error for a 95% confidence level = Z x (σ / √n)

  • Z for a 95% confidence level = 1.96
  • standard deviation (σ) = $160
  • sample size (n) = 280

the margin of error for a 95% confidence level = 1.96 x ($160 / √280) = 1.96 x ($160 / 16.733) = 1.96 x $9.56 = $18.74

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