Answer:
852g
Explanation:
From the question given, we obtained the following information:
Molarity = 3M
Volume = 2L
Mole =?
First, we need to find the number of mole of Na2SO4 present in 2L of the solution. This is achieved by doing the following:
Molarity = mole /Volume
Mole = Molarity x Volume
Mole = 3 x 2 = 6moles
Next, we'll find the molar mass of Na2SO4, as illustrated below:
Molar Mass of Na2SO4 = (23x2)+32+(16x4) = 46 + 32 + 64 = 142g/mol
Recall:
Number of mole = Mass /Molar Mass
Mass = number of mole x molar Mass
Mass = 6 x 142 = 852g
