Incomplete question.The complete question is here
A seagull can fly at a velocity of 9.00 m/s in still air.If it takes the bird 15 min to travel 5.8 km relative to the Earth, what is the velocity of the wind, in meters per second, relative to the Earth? Take the direction of travel of the seagull to be positive.
Answer:
[tex]V_{AE}=-2.55i.m/s[/tex]
Explanation:
Given data
[tex]v_{BA}=9m/s\\ R=5.8Km=5800m\\t=15min=900s[/tex]
The velocity of bird:
[tex]v_{BE}=R/t=5800m/900s \\v_{BE}=6.444m/s[/tex]
Assume that:
[tex]V_{BA}=9im/s[/tex]
The bird feels the air stream is equal in opposite direction or:
[tex]V_{BE}=6.44i.m/s[/tex]
According to the relative motion concept the velocity of wind VAE is given by:
[tex]V_{AE}=V_{BE}-V_{BA}\\V_{AE}=6.44i-9i\\V_{AE}=-2.55im/s[/tex]
