Answer:
0.342g of octane
Explanation:
First let us generate a balanced equation for the reaction this is illustrated below:
2C8H18 + 25O2 —> 16CO2 + 18H20
Next, we'll calculate the molar mass and masses of C8H18 and O2
Molar Mass of C8H18 = (12x8) + (18x1 ) = 96 + 18 = 114g/mol
Mass of C8H18 from the balanced equation = 2 x 114 = 228g
Molar Mass of O2 = 16 x 2 = 32g/mol
Mass of O2 from the balanced equation = 25 x 32 = 800g
From the equation,
228g of octane(C8H18) were consumed by 800g of O2.
Therefore, Xg of octane will be consumed by 1.2g of O2 i.e
Xg of octane = (228 x 1.2)/800 = 0.342g
Therefore 0.342g of octane will be consumed