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Five moles of an ideal monatomic gas with an initial temperature of 127∘C expand and, in the process, absorb 1500 J of heat and do 2100 J of work. What is the final temperature of the gas?

Respuesta :

lublana

Answer:

[tex]117.38^{\circ}C[/tex]

Explanation:

We are given that

Initial temperature=[tex]T_1=127^{\circ}[/tex]

Number of moles=n=5

Heat absorbed,Q=1500 J

Work done=W=2100 J

We have to find the final temperature  of the gas.

[tex]\Delta U=Q-W=1500-2100=-600 J[/tex]

[tex]T_2=\frac{2\Delta U}{3nR}+T_1[/tex]

Where R=8.314 J/mol-K

Using the formula

[tex]T_2=\frac{2\times (-600)}{3\times 5\times 8.314}+127^{\circ} C[/tex]

[tex]T_2=117.38^{\circ}C[/tex]