The volume of a sample of carbon monoxide is 354 mL at 3.52 atm. What will the volume be when the pressure is reduced to 1.85 atm, assuming the temperature is constant.

Respuesta :

The volume will be 674 ml.

Explanation:

As the temperature is said to be constant, then the present system will be obeying Boyle's law. So according to this law, the volume of a gaseous system is inversely proportional to the pressure of the system at constant temperature and number of moles.

So according to this law, [tex]P_{1} V_{1} = P_{2} V_{2}[/tex]

As here the initial pressure is 3.52 atm and the initial volume is 354 mL with the reduced pressure as 1.85 atm. Since, there is a decrease in the pressure, there tends to increase in the volume.

So, [tex]354 * 3.52 = 1.85 * V_{2}[/tex]

[tex]V_{2} =674 ml[/tex]

So, the volume will be 674 ml.